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<item>
            <title>[PIPE2D-508] Find out translation from real frd to `frd_sigma` parameter 2d psf_model </title>
                <link>https://pfspipe.ipmu.jp/jira/browse/PIPE2D-508</link>
                <project id="10002" key="PIPE2D">DRP 2-D Pipeline</project>
                    <description>&lt;p&gt;At the moment `frd_sigma` parameter in the 2d psf_model takes values which are not connected with actual values for the frd (focal ratio degradation). The values that seem to fit the data are around 0.05 to 0.1, but it is not clear what values of frd these numbers actually are. This is because I never made sure that `frd_sigma` corresponds to some realistic values of frd. The task here it to figure how how are values of&#160;`frd_sigma` connected with actual values of frd.&#160;&lt;/p&gt;</description>
                <environment></environment>
        <key id="14193">PIPE2D-508</key>
            <summary>Find out translation from real frd to `frd_sigma` parameter 2d psf_model </summary>
                <type id="3" iconUrl="https://pfspipe.ipmu.jp/jira/secure/viewavatar?size=xsmall&amp;avatarId=10518&amp;avatarType=issuetype">Task</type>
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                                        <assignee username="bbelland">Brent Belland</assignee>
                                    <reporter username="ncaplar">ncaplar</reporter>
                        <labels>
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                <created>Mon, 27 Jan 2020 14:21:41 +0000</created>
                <updated>Mon, 4 Jan 2021 20:23:12 +0000</updated>
                            <resolved>Mon, 31 Aug 2020 22:48:08 +0000</resolved>
                                                                        <due></due>
                            <votes>0</votes>
                                    <watches>2</watches>
                                                                <comments>
                            <comment id="16652" author="bbelland" created="Fri, 31 Jan 2020 21:58:18 +0000"  >&lt;p&gt;It appears to me that we can convert from frd_sigma if we know the f number of the input beam light. In the code, frd_sigma is just the fraction of an image length corresponding to the convolution (with a factor of sqrt(2) due to.how scipy.special.erf works). If effective_illum_radius as passed to the code represents the fraction of the image length that the pupil image takes up, then the ratio of frd_sigma/effective_illum_radius is the conversion factor between the angular size of the pupil image and the angular size of the FRD (i.e., the &apos;actual&apos; value of FRD). I believe that generally f/2.8 is used in the fibers (though you have the correct values for each individual measurement), corresponding to a numerical aperture of 0.17857 (=1/&lt;span class=&quot;error&quot;&gt;&amp;#91;2*2.8&amp;#93;&lt;/span&gt;).&lt;/p&gt;

&lt;p&gt;&#160;&lt;/p&gt;

&lt;p&gt;It&apos;s simplistic, but I think in general &quot;actual&quot; frd in radians = (Numerical Aperture)*sqrt(2)*frd_sigma/(effective_illum_radius).&lt;/p&gt;

&lt;p&gt;&#160;&lt;/p&gt;

&lt;p&gt;As a sanity check, if effective_illum_radius ~ 1 and frd_sigma~0.05-0.1, then for f/2.8 the frd ranges from 12.6 milliradians to 25 milliradians, which sounds a little high but reasonable depending on the experimental setup.&lt;/p&gt;

&lt;p&gt;&#160;&lt;/p&gt;

&lt;p&gt;I&apos;ll follow up with lab data to verify.&lt;/p&gt;</comment>
                            <comment id="17603" author="bbelland" created="Mon, 31 Aug 2020 22:48:08 +0000"  >&lt;p&gt;FRD is incorporated into all analysis up to this point and in the foreseeable future with this equation.&lt;/p&gt;</comment>
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