[FIBERALLOC-4] Position angle in different time Created: 09/Nov/16 Updated: 02/May/18 Resolved: 02/May/18 |
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| Status: | Done |
| Project: | Target to fiber allocation and configuration |
| Component/s: | None |
| Affects Version/s: | None |
| Fix Version/s: | None |
| Type: | Story | Priority: | Major |
| Reporter: | Kiyoto Yabe | Assignee: | Martin Reinecke |
| Resolution: | Done | Votes: | 0 |
| Labels: | None | ||
| Remaining Estimate: | Not Specified | ||
| Time Spent: | Not Specified | ||
| Original Estimate: | Not Specified | ||
| Description |
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I found the configuration for PA=0 deg. did not look like PA=0. I ran the code as follows: ./ets_demo assigner=naive input=ets_test_data.dat fract=0.90 output=tmp.out ra=34.0 dec=-4.5 posang=0.0 dposang=0.0 nposang=1 dptg=0.0 nptg=1 time=2016-11-09T08:00:00Z "ets_test_data.dat" can be found here: Using the coordinate of allocated objects, the PFI FoV looks rotated against the north direction, and this tilt angle seem to depend on the observing time set. What kind of effect is this from? |
| Comments |
| Comment by Martin Reinecke [ 09/Nov/16 ] |
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I fear this is due to my insufficient knowledge how the position angle is defined. My expectation is that its definition can be deduced by the transformation between the reference frame of the PFS and the telescope itself. |
| Comment by Kiyoto Yabe [ 10/Nov/16 ] |
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I will find out documents (if they exist...). For my reference, could you point out where you calculate the angle in the code please? (Sorry, I'm not a good C programmer...) |
| Comment by Martin Reinecke [ 10/Nov/16 ] |
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Sure! |
| Comment by Kiyoto Yabe [ 11/Nov/16 ] |
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OK, I will check that in details. Yes, it is true that y axis should point north if PA is 0, but the result does not seem to be so, if I plot the output RA and Dec... I found that Maximilian may also know something. We should contact people in Subaru but he can directly ask to someone (for example Eric Jeschke-san). |
| Comment by mxhf [ 11/Nov/16 ] |
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Dear Yabe san, dear Martin, reading the last two comment carefully, it seems that there is a misunderstanding. Martin: PA = 0 is indeed straight North. Was that clear? The orientation of the angle is a bit less clear, but positive angle going east of North tends to be the standard. Note, this is the Position Angle. So, PA = 0 does not point to Zenith but Polaris (more or less). This can be confused with the Parallactic angle. To avoid confusion people do *notP usually abbreviate the latter with "PA" but with "parang" or so. Maximilian |
| Comment by Martin Reinecke [ 11/Nov/16 ] |
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Thank you for your inputs. I will try and digest the explanation over the weekend. |
| Comment by Martin Reinecke [ 11/Nov/16 ] |
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I think I got it... associating "PA=0" with "y axis points toward the zenith" was of course a naive conclusion. The celestial Pole makes a lot more sense. |
| Comment by Martin Reinecke [ 14/Nov/16 ] |
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I have pushed a change that determines the PA relative to the celestial pole now. Tests indicate that the shape of the output FoV no longer depends on time and also appears to have the correct orientation. |
| Comment by Kiyoto Yabe [ 16/Nov/16 ] |
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Thank you, Martin. It seems that PFI X and Y coordinates change if we set the same position center and position angle but a different time (probably it depends on ALT). Did you take into consideration the atmospheric differential refraction? or the conversion between RA-Dec and X-Y depends on ALT now? |
| Comment by Martin Reinecke [ 16/Nov/16 ] |
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Yes, differential refraction is taken into account (as well as nutation and aberration). Is this sufficient to explain the shifts you see? |
| Comment by Martin Reinecke [ 16/Nov/16 ] |
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I just verified that by switching refraction off (in the source code), the time-dependent shifts in x and y positions become much smaller. So it appears that differential refraction indeed causes most of the differences. |
| Comment by Kiyoto Yabe [ 17/Nov/16 ] |
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OK, thank you. Then, I think we are ready now for the distribution with this version. |